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Popular >

foci x^2=28y

Solution

foci

x^{2} = 28 y

Solution

(0, 7)

Solution steps

Rewrite

x^{2} = 28 y

in the standard form:

4 \cdot 7 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 7

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 7)

Refine

(0, 7)

Popular Examples

axis y=2-x-2x^2 axis

y = 2 - x - 2 x^{2}

foci (x^2)/8+(y^2)/3 =1 foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

vertices f(x)=x^2+6x+5 vertices

f (x) = x^{2} + 6 x + 5

4x^2-12y^2-16x-72y-44=0

4 x^{2} - 12 y^{2} - 16 x - 72 y - 44 = 0

directrix y^2=-2x directrix

y^{2} = - 2 x

Frequently Asked Questions (FAQ)

What is the foci x^2=28y ?
The foci x^2=28y is (0,7)