What is the directrix (y-0)^2=-4sqrt(3)(x-0) ?

The directrix (y-0)^2=-4sqrt(3)(x-0) is x=sqrt(3)

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directrix (y-0)^2=-4sqrt(3)(x-0)

directrix

(y - 0)^{2} = - 43 (x - 0)

x = 3

Solution steps

Rewrite

(y - 0)^{2} = - 43 (x - 0)

in the standard form:

4 (- 3) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 3)

Refine

x = 3

y = x^{2} + 22

- 29 x^{2} + 1388 x - 10040

x = - 2 y^{2}

y^{2} - 6 y + 3

3 y^{2} + 4 x - 24 y + 44 = 0

What is the directrix (y-0)^2=-4sqrt(3)(x-0) ?
The directrix (y-0)^2=-4sqrt(3)(x-0) is x=sqrt(3)