What is the directrix-29x^2+1388x-10040 ?

The directrix-29x^2+1388x-10040 is y= 761905/116

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directrix-29x^2+1388x-10040

directrix

- 29 x^{2} + 1388 x - 10040

y = \frac{761905}{116}

Solution steps

Rewrite

y = - 29 x^{2} + 1388 x - 10040

in the standard form

4 (- \frac{1}{116}) (y - \frac{190476}{29}) = (x - \frac{694}{29})^{2}

(h, k) = (\frac{694}{29}, \frac{190476}{29}), p = - \frac{1}{116}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{694}{29}, \frac{190476}{29})

y-coordinate

y = \frac{190476}{29} - p

y = \frac{190476}{29} - (- \frac{1}{116})

Refine

y = \frac{761905}{116}

x = - 2 y^{2}

y^{2} - 6 y + 3

3 y^{2} + 4 x - 24 y + 44 = 0

y = (x - 4) (x - 2)

(x - 4)^{2} - 2 (y + 8) = 0

What is the directrix-29x^2+1388x-10040 ?
The directrix-29x^2+1388x-10040 is y= 761905/116