What is the directrix x^2=4y+8 ?

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directrix x^2=4y+8

directrix

x^{2} = 4 y + 8

y = - 3

Solution steps

Rewrite

x^{2} = 4 y + 8

in the standard form:

4 \cdot 1 \cdot (y - (- 2)) = (x - 0)^{2}

(h, k) = (0, - 2), p = 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 2)

y-coordinate

y = - 2 - p

y = - 2 - 1

Refine

y = - 3

\frac{9 x ^{2}}{2}

2 x^{2} + 8 x + 13

2 x^{2} - 4 x + 9

3 x^{2} - 31 x + 56 - (x - 8)

y = - 2.1 x^{2} + 410 x - 1340