What is the directrix 3x^2-31x+56-(x-8) ?

The directrix 3x^2-31x+56-(x-8) is y=-257/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix 3x^2-31x+56-(x-8)

directrix

y = - \frac{257}{12}

Solution steps

Rewrite

y = 3 x^{2} - 31 x + 56 - (x - 8)

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{64}{3})) = (x - \frac{16}{3})^{2}

(h, k) = (\frac{16}{3}, - \frac{64}{3}), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{16}{3}, - \frac{64}{3})

y-coordinate

y = - \frac{64}{3} - p

y = - \frac{64}{3} - \frac{1}{12}

Refine

y = - \frac{257}{12}

What is the directrix 3x^2-31x+56-(x-8) ?
The directrix 3x^2-31x+56-(x-8) is y=-257/12