What is the directrix y=-1/4 (x^2-14x+13) ?

The directrix y=-1/4 (x^2-14x+13) is y=10

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directrix y=-1/4 (x^2-14x+13)

directrix

y = - \frac{1}{4} (x^{2} - 14 x + 13)

y = 10

Solution steps

Rewrite

y = - \frac{1}{4} (x^{2} - 14 x + 13)

in the standard form

4 (- 1) (y - 9) = (x - 7)^{2}

(h, k) = (7, 9), p = - 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(7, 9)

y-coordinate

y = 9 - p

y = 9 - (- 1)

Refine

y = 10

x^{2} + 5

y^{2} = - 32 x

(x + 2)^{2} = - (y - 1)

y = - 8 x^{2} + 4

3 x^{2} + 6 x - 4

What is the directrix y=-1/4 (x^2-14x+13) ?
The directrix y=-1/4 (x^2-14x+13) is y=10