What is the directrix y^2=-32x ?

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directrix y^2=-32x

directrix

y^{2} = - 32 x

x = 8

Solution steps

Rewrite

y^{2} = - 32 x

in the standard form:

4 (- 8) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 8

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 8)

Refine

x = 8

(x + 2)^{2} = - (y - 1)

y = - 8 x^{2} + 4

3 x^{2} + 6 x - 4

x^{2} + 2 x - 12 y + 37 = 0

2 x^{2} + 16 x + 35