What is the directrix y=x^2-8 ?

The directrix y=x^2-8 is y=-33/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

directrix y=x^2-8

directrix

y = - \frac{33}{4}

Solution steps

Rewrite

y = x^{2} - 8

in the standard form:

4 \cdot \frac{1}{4} (y - (- 8)) = (x - 0)^{2}

(h, k) = (0, - 8), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 8)

y-coordinate

y = - 8 - p

y = - 8 - \frac{1}{4}

Refine

y = - \frac{33}{4}