What is the directrix x+5+(y-3)^2=0 ?

The directrix x+5+(y-3)^2=0 is x=-19/4

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directrix x+5+(y-3)^2=0

directrix

x = - \frac{19}{4}

Solution steps

Rewrite

x + 5 + (y - 3)^{2} = 0

in the standard form:

4 (- \frac{1}{4}) (x - (- 5)) = (y - 3)^{2}

(h, k) = (- 5, 3), p = - \frac{1}{4}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 5, 3)

x-coordinate

x = - 5 - p

x = - 5 - (- \frac{1}{4})

Refine

x = - \frac{19}{4}