What is the directrix (y-3)^2=4(x+2) ?

The directrix (y-3)^2=4(x+2) is x=-3

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directrix (y-3)^2=4(x+2)

directrix

(y - 3)^{2} = 4 (x + 2)

x = - 3

Solution steps

Rewrite

(y - 3)^{2} = 4 (x + 2)

in the standard form:

4 \cdot 1 \cdot (x - (- 2)) = (y - 3)^{2}

(h, k) = (- 2, 3), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 3)

x-coordinate

x = - 2 - p

x = - 2 - 1

Refine

x = - 3

y = + (x - 7)^{2}

- 2 x^{2} + 25 x

4 t^{2} + 1

y = (x + 5)^{2}

y = 3 x^{2} - 2