What is the directrix y=+(x-7)^2 ?

The directrix y=+(x-7)^2 is y=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=+(x-7)^2

directrix

y = + (x - 7)^{2}

y = - \frac{1}{4}

Solution steps

Rewrite

y = (x - 7)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 7)^{2}

(h, k) = (7, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(7, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

- 2 x^{2} + 25 x

4 t^{2} + 1

y = (x + 5)^{2}

y = 3 x^{2} - 2

y = 3 x^{2} - 5