What is the directrix y=-3x^2+12x-4 ?

The directrix y=-3x^2+12x-4 is y= 97/12

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directrix y=-3x^2+12x-4

directrix

y = - 3 x^{2} + 12 x - 4

y = \frac{97}{12}

Solution steps

Rewrite

y = - 3 x^{2} + 12 x - 4

in the standard form

4 (- \frac{1}{12}) (y - 8) = (x - 2)^{2}

(h, k) = (2, 8), p = - \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(2, 8)

y-coordinate

y = 8 - p

y = 8 - (- \frac{1}{12})

Refine

y = \frac{97}{12}

y = x^{2} - 2 x + 8

4 y^{2} - 48 x - 20 y = 71

y = (2 x + 5)^{2}

y = (x - 4)^{2} + 2

4 t - 9 t^{2}