What is the directrix y=(x-4)^2+2 ?

The directrix y=(x-4)^2+2 is y= 7/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=(x-4)^2+2

directrix

y = (x - 4)^{2} + 2

y = \frac{7}{4}

Solution steps

Rewrite

y = (x - 4)^{2} + 2

in the standard form:

4 \cdot \frac{1}{4} (y - 2) = (x - 4)^{2}

(h, k) = (4, 2), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(4, 2)

y-coordinate

y = 2 - p

y = 2 - \frac{1}{4}

Refine

y = \frac{7}{4}

4 t - 9 t^{2}

y = (x + 2)^{2} - 3

- 2 x^{2} + 12 x - 2

4 x^{2} - 8 x - 3

y = - 9 x^{2}