What is the directrix-1/20 y^2 ?

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directrix-1/20 y^2

directrix

- \frac{1}{20} y^{2}

x = 5

Solution steps

Rewrite

x = - \frac{1}{20} y^{2}

in the standard form:

4 (- 5) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 5

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 5)

Refine

x = 5

y = x^{2} - 4 x + 3

(x - 2)^{2} = 8 (y - 1)

- x^{2} + 6 x - 9

(x + 3)^{2} = 24 (y - 1)

x^{2} + 2 x + 1