What is the directrix (x+3)^2=24(y-1) ?

The directrix (x+3)^2=24(y-1) is y=-5

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directrix (x+3)^2=24(y-1)

directrix

(x + 3)^{2} = 24 (y - 1)

y = - 5

Solution steps

Rewrite

(x + 3)^{2} = 24 (y - 1)

in the standard form:

4 \cdot 6 (y - 1) = (x - (- 3))^{2}

(h, k) = (- 3, 1), p = 6

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 3, 1)

y-coordinate

y = 1 - p

y = 1 - 6

Refine

y = - 5

x^{2} + 2 x + 1

x^{2} - 20 x + 100

y = 2 x^{2} + 4

y = 3 x^{2} - x - 4

(x - h)^{2} = 4 p (y - k)