What is the directrix y=(x^25x8)/(x3) ?

The directrix y=(x^25x8)/(x3) is y=-3/160

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=(x^25x8)/(x3)

directrix

y = \frac{x ^{2} 5 x 8}{x 3}

y = - \frac{3}{160}

Solution steps

Rewrite

y = \frac{x ^{2} \cdot 5 x \cdot 8}{x \cdot 3}

in the standard form

4 \cdot \frac{3}{160} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{3}{160}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{3}{160}

Refine

y = - \frac{3}{160}

(x + 5)^{2} = - 20 (y - 2)

x^{2} + 4 x - 3

x^{2} - y = 0

- 4 (y - 10) = (x - 6)^{2}

4 - 7 x^{2}

What is the directrix y=(x^25x8)/(x3) ?
The directrix y=(x^25x8)/(x3) is y=-3/160