What is the directrix x^2+4x-3 ?

The directrix x^2+4x-3 is y=-29/4

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directrix x^2+4x-3

directrix

x^{2} + 4 x - 3

y = - \frac{29}{4}

Solution steps

Rewrite

y = x^{2} + 4 x - 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 7)) = (x - (- 2))^{2}

(h, k) = (- 2, - 7), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, - 7)

y-coordinate

y = - 7 - p

y = - 7 - \frac{1}{4}

Refine

y = - \frac{29}{4}

x^{2} - y = 0

- 4 (y - 10) = (x - 6)^{2}

4 - 7 x^{2}

3 x^{2} - x - 4

y = x^{2} - 10 x - 4