What is the directrix x^2=10y ?

The directrix x^2=10y is y=-5/2

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directrix x^2=10y

directrix

x^{2} = 10 y

y = - \frac{5}{2}

Solution steps

Rewrite

x^{2} = 10 y

in the standard form:

4 \cdot \frac{5}{2} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{5}{2}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{5}{2}

Refine

y = - \frac{5}{2}

y = 6 x^{2} - 3 x 5

\frac{1}{3} (x + 2)^{2} - 3

x^{2} - 6 x + 5 y = - 34

y^{2} - 8 x = 0

x^{2} + 8 x + 18