What is the directrix y^2-8x=0 ?

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directrix y^2-8x=0

directrix

y^{2} - 8 x = 0

x = - 2

Solution steps

Rewrite

y^{2} - 8 x = 0

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 2

Refine

x = - 2

x^{2} + 8 x + 18

(y - 2)^{2} = 12 (x + 1)

y = x^{2} - 5 x - 24

y = - 4 (x + 10)^{2} + 6

y^{2} - 12 y - 4 x + 28 = 0