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Popular >

x^2+2y^2=2

Solution

x^{2} + 2 y^{2} = 2

Solution

(h, k) = (0, 0), a = 2, b = 1

Solution steps

x^{2} + 2 y^{2} = 2

Rewrite

x^{2} + 2 y^{2} = 2

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

Popular Examples

vertices f(x)=x^2-4x vertices

f (x) = x^{2} - 4 x

2y^2+x+20y+51=0

2 y^{2} + x + 20 y + 51 = 0

foci 9x^2-4y^2=36 foci

9 x^{2} - 4 y^{2} = 36

x^{2} + y^{2} < 9

(x^2}{64}+\frac{y^2)/4 =1

\frac{x ^{2}}{64} + \frac{y ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is x^2+2y^2=2 ?
The solution to x^2+2y^2=2 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=1