What is the foci 9x^2-4y^2=36 ?

The foci 9x^2-4y^2=36 is (sqrt(13),0),(-sqrt(13),0)

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foci 9x^2-4y^2=36

foci

9 x^{2} - 4 y^{2} = 36

(13, 0), (- 13, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 13

(0 + 13, 0), (0 - 13, 0)

Refine

(13, 0), (- 13, 0)

x^{2} + y^{2} < 9

\frac{x ^{2}}{64} + \frac{y ^{2}}{4} = 1

(y - 2)^{2} = (x - 1)^{2} + (y + 4)^{2}

x^{2} + 2 x + y^{2} = 8

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

What is the foci 9x^2-4y^2=36 ?
The foci 9x^2-4y^2=36 is (sqrt(13),0),(-sqrt(13),0)