{
"query": {
"display": "$$x=y-y^{2}$$",
"symbolab_question": "CONIC#x=y-y^{2}"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(\\frac{1}{4},\\frac{1}{2}),p=-\\frac{1}{4}"
},
"steps": {
"type": "interim",
"title": "$$x=y-y^{2}:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(\\frac{1}{4},\\:\\frac{1}{2}\\right),\\:$$and focal length $$|p|=\\frac{1}{4}$$",
"input": "x=y-y^{2}",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(x-h\\right)=\\left(y-k\\right)^{2}\\:$$ is the standard equation for a right-left facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$x=y-y^{2}\\:$$in the standard form",
"input": "x=y-y^{2}",
"steps": [
{
"type": "interim",
"title": "Complete the square $$y-y^{2}:{\\quad}-\\left(y-\\frac{1}{2}\\right)^{2}+\\frac{1}{4}$$",
"input": "y-y^{2}",
"steps": [
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c$$",
"result": "-y^{2}+y"
},
{
"type": "step",
"primary": "Write $$-y^{2}+y\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-1$$"
],
"result": "-\\left(y^{2}-y\\right)"
},
{
"type": "interim",
"title": "$$2a=-1{\\quad:\\quad}a=-\\frac{1}{2}$$",
"input": "2a=-1",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=-1",
"result": "a=-\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(-\\frac{1}{2}\\right)^{2}\\:$$",
"result": "-\\left(y^{2}-y+\\left(-\\frac{1}{2}\\right)^{2}-\\left(-\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$y^{2}-1y+\\left(-\\frac{1}{2}\\right)^{2}=\\left(y-\\frac{1}{2}\\right)^{2}$$",
"Complete the square"
],
"result": "-\\left(\\left(y-\\frac{1}{2}\\right)^{2}-\\left(-\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-\\left(y-\\frac{1}{2}\\right)^{2}+\\frac{1}{4}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "x=-\\left(y-\\frac{1}{2}\\right)^{2}+\\frac{1}{4}"
},
{
"type": "step",
"primary": "Subtract $$\\frac{1}{4}$$ from both sides",
"result": "x-\\frac{1}{4}=-\\left(y-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-1$$",
"result": "-\\left(x-\\frac{1}{4}\\right)=\\left(y-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(x-\\frac{1}{4}\\right)=\\left(y-\\frac{1}{2}\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(x-\\frac{1}{4}\\right)=\\left(y-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(\\frac{1}{4},\\:\\frac{1}{2}\\right),\\:p=-\\frac{1}{4}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{4(-\\frac{1}{4})(x-\\frac{1}{4})}+\\frac{1}{2}",
"displayFormula": "4(-\\frac{1}{4})(x-\\frac{1}{4})=(y-\\frac{1}{2})^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{4(-\\frac{1}{4})(x-\\frac{1}{4})}+\\frac{1}{2}",
"displayFormula": "4(-\\frac{1}{4})(x-\\frac{1}{4})=(y-\\frac{1}{2})^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "x=\\frac{1}{2}",
"displayFormula": "x=\\frac{1}{2}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(\\frac{1}{4},\\frac{1}{2})",
"(0,\\frac{1}{2})"
],
"pointsDecimal": [
{
"fst": 0.25,
"snd": 0.5
},
{
"fst": 0,
"snd": 0.5
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{1}{4})(x-\\frac{1}{4})=(y-\\frac{1}{2})^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -2.5625,
"xMax": 3.0625,
"yMin": -2.3125,
"yMax": 3.3125
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is x=y-y^2 ?
The solution to x=y-y^2 is Parabola with (h,k)=(1/4 , 1/2),p=-1/4