What is x^2-2x+y^2+2y=7 ?

The solution to x^2-2x+y^2+2y=7 is Circle with (a,b)=(1,-1),r=3

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x^2-2x+y^2+2y=7

x^{2} - 2 x + y^{2} + 2 y = 7

(a, b) = (1, - 1), r = 3

Solution steps

x^{2} - 2 x + y^{2} + 2 y = 7

Rewrite

x^{2} - 2 x + y^{2} + 2 y = 7

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 3

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

y, 36 x^{2} - 25 y^{2} + 144 x - 50 y + 119 = 0

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

x^{2} + y^{2} \leq 4

f (x) = x^{2} + 4 x + 3

What is x^2-2x+y^2+2y=7 ?
The solution to x^2-2x+y^2+2y=7 is Circle with (a,b)=(1,-1),r=3