{
"query": {
"display": "$$x^{2}-2x+y^{2}+2y=7$$",
"symbolab_question": "CONIC#x^{2}-2x+y^{2}+2y=7"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Circle",
"subTopic": "formula",
"default": "(a,b)=(1,-1),r=3"
},
"steps": {
"type": "interim",
"title": "$$x^{2}-2x+y^{2}+2y=7:\\quad$$Circle with center at $$\\left(1,\\:-1\\right)\\:$$and radius $$r=3$$",
"input": "x^{2}-2x+y^{2}+2y=7",
"steps": [
{
"type": "definition",
"title": "Circle Equation",
"text": "$$\\left(x−a\\right)^2+\\left(y−b\\right)^2=r^2\\:\\:$$is the circle equation with a radius r, centered at $$\\left(a,\\:b\\right)$$"
},
{
"type": "interim",
"title": "Rewrite $$x^{2}-2x+y^{2}+2y=7\\:$$in the form of the standard circle equation",
"input": "x^{2}-2x+y^{2}+2y=7",
"steps": [
{
"type": "step",
"primary": "Group x-variables and y-variables together",
"result": "\\left(x^{2}-2x\\right)+\\left(y^{2}+2y\\right)=7"
},
{
"type": "step",
"primary": "Convert $$x\\:$$to square form",
"result": "\\left(x^{2}-2x+1\\right)+\\left(y^{2}+2y\\right)=7+1"
},
{
"type": "step",
"primary": "Convert to square form",
"result": "\\left(x-1\\right)^{2}+\\left(y^{2}+2y\\right)=7+1"
},
{
"type": "step",
"primary": "Convert $$y\\:$$to square form",
"result": "\\left(x-1\\right)^{2}+\\left(y^{2}+2y+1\\right)=7+1+1"
},
{
"type": "step",
"primary": "Convert to square form",
"result": "\\left(x-1\\right)^{2}+\\left(y+1\\right)^{2}=7+1+1"
},
{
"type": "step",
"primary": "Refine $$7+1+1$$",
"result": "\\left(x-1\\right)^{2}+\\left(y+1\\right)^{2}=9"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "\\left(x-1\\right)^{2}+\\left(y-\\left(-1\\right)\\right)^{2}=3^{2}"
}
],
"meta": {
"interimType": "Circle Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "\\left(x-1\\right)^{2}+\\left(y-\\left(-1\\right)\\right)^{2}=3^{2}"
},
{
"type": "step",
"primary": "Therefore the circle properties are:",
"result": "\\left(a,\\:b\\right)=\\left(1,\\:-1\\right),\\:r=3"
}
],
"meta": {
"solvingClass": "Circle"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{3^{2}-(x-1)^{2}}-1",
"displayFormula": "(x-1)^{2}+(y-(-1))^{2}=3^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{3^{2}-(x-1)^{2}}-1",
"displayFormula": "(x-1)^{2}+(y-(-1))^{2}=3^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(1,-1)"
],
"pointsDecimal": [
{
"fst": 1,
"snd": -1
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{Center}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"linesToDraw": [
{
"p1x": "1",
"p1y": "-1",
"p2x": "3.1213203435596",
"p2y": "1.1213203435596",
"attributes": {
"color": "GRAY",
"lineType": "BOLD",
"labels": [
"\\mathrm{radius=}3"
],
"isAsymptote": false
}
}
],
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "(x-1)^{2}+(y-(-1))^{2}=3^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -5.75,
"xMax": 7.75,
"yMin": -7.75,
"yMax": 5.75
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is x^2-2x+y^2+2y=7 ?
The solution to x^2-2x+y^2+2y=7 is Circle with (a,b)=(1,-1),r=3