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Popular >

foci x^2+6x+16

Solution

foci

x^{2} + 6 x + 16

Solution

(- 3, \frac{29}{4})

Solution steps

Rewrite

y = x^{2} + 6 x + 16

in the standard form

4 \cdot \frac{1}{4} (y - 7) = (x - (- 3))^{2}

(h, k) = (- 3, 7), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 3, 7)

along the y-axis

(- 3, 7 + p)

= (- 3, 7 + \frac{1}{4})

Refine

(- 3, \frac{29}{4})

Popular Examples

foci x=-2(y-2)^2+7 foci

x = - 2 (y - 2)^{2} + 7

foci (2x-1)(5x-6)foci

(2 x - 1) (5 x - 6)

foci 20t-t^2 foci

20 t - t^{2}

foci y^2-12y-4x=-28 foci

y^{2} - 12 y - 4 x = - 28

foci (x-1)^2=8(y-k)foci

(x - 1)^{2} = 8 (y - k)

Frequently Asked Questions (FAQ)

What is the foci x^2+6x+16 ?
The foci x^2+6x+16 is (-3, 29/4)