What is the foci x=-2(y-2)^2+7 ?

The foci x=-2(y-2)^2+7 is (55/8 ,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x=-2(y-2)^2+7

foci

x = - 2 (y - 2)^{2} + 7

(\frac{55}{8}, 2)

Solution steps

Rewrite

x = - 2 (y - 2)^{2} + 7

in the standard form:

4 (- \frac{1}{8}) (x - 7) = (y - 2)^{2}

(h, k) = (7, 2), p = - \frac{1}{8}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(7, 2)

along the x-axis

(7 + p, 2)

= (7 + (- \frac{1}{8}), 2)

Refine

(\frac{55}{8}, 2)

(2 x - 1) (5 x - 6)

20 t - t^{2}

y^{2} - 12 y - 4 x = - 28

(x - 1)^{2} = 8 (y - k)

(y - 4)^{2} = 8 (x - 3)