What is the foci y=-0.1(x+12.58)^2+6.37 ?

The foci y=-0.1(x+12.58)^2+6.37 is (-12.58,3.87)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=-0.1(x+12.58)^2+6.37

foci

y = - 0.1 (x + 12.58)^{2} + 6.37

(- 12.58, 3.87)

Solution steps

Rewrite

y = - 0.1 (x + 12.58)^{2} + 6.37

in the standard form:

4 (- 2.5) (y - 6.37) = (x - (- 12.58))^{2}

(h, k) = (- 12.58, 6.37), p = - 2.5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 12.58, 6.37)

along the y-axis

(- 12.58, 6.37 + p)

= (- 12.58, 6.37 + (- 2.5))

Refine

(- 12.58, 3.87)

8 x^{2} + 1

y = - 2 x^{2} - 3

(x - 3)^{2} = - 8 (y - 4)

- 2 x^{2} + 6 x - 3

y = 6 x^{2} - 29 x - 5

What is the foci y=-0.1(x+12.58)^2+6.37 ?
The foci y=-0.1(x+12.58)^2+6.37 is (-12.58,3.87)