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Popular >

foci 8x^2+1

Solution

foci

8 x^{2} + 1

Solution

(0, \frac{33}{32})

Solution steps

Rewrite

y = 8 x^{2} + 1

in the standard form:

4 \cdot \frac{1}{32} (y - 1) = (x - 0)^{2}

(h, k) = (0, 1), p = \frac{1}{32}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 1)

along the y-axis

(0, 1 + p)

= (0, 1 + \frac{1}{32})

Refine

(0, \frac{33}{32})

Popular Examples

foci y=-2x^2-3 foci

y = - 2 x^{2} - 3

foci (x-3)^2=-8(y-4)foci

(x - 3)^{2} = - 8 (y - 4)

foci-2x^2+6x-3 foci

- 2 x^{2} + 6 x - 3

foci y=6x^2-29x-5 foci

y = 6 x^{2} - 29 x - 5

foci y=1-3x-x^2 foci

y = 1 - 3 x - x^{2}

Frequently Asked Questions (FAQ)

What is the foci 8x^2+1 ?
The foci 8x^2+1 is (0, 33/32)