What is the foci-x^2+16x-94 ?

The foci-x^2+16x-94 is (8,-121/4)

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foci-x^2+16x-94

foci

- x^{2} + 16 x - 94

(8, - \frac{121}{4})

Solution steps

Rewrite

y = - x^{2} + 16 x - 94

in the standard form

4 (- \frac{1}{4}) (y - (- 30)) = (x - 8)^{2}

(h, k) = (8, - 30), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(8, - 30)

along the y-axis

(8, - 30 + p)

= (8, - 30 + (- \frac{1}{4}))

Refine

(8, - \frac{121}{4})

2 x^{2} + 24 x - 16

(y + 1.5)^{2} = 4 (x - 2)

\frac{1}{2} x^{2} - 7 x + 7

(2 x - 5)^{2}

y = + x^{2} + 6 x + 3