What is the foci 2x^2+24x-16 ?

The foci 2x^2+24x-16 is (-6,-703/8)

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foci 2x^2+24x-16

foci

2 x^{2} + 24 x - 16

(- 6, - \frac{703}{8})

Solution steps

Rewrite

y = 2 x^{2} + 24 x - 16

in the standard form

4 \cdot \frac{1}{8} (y - (- 88)) = (x - (- 6))^{2}

(h, k) = (- 6, - 88), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 6, - 88)

along the y-axis

(- 6, - 88 + p)

= (- 6, - 88 + \frac{1}{8})

Refine

(- 6, - \frac{703}{8})

(y + 1.5)^{2} = 4 (x - 2)

\frac{1}{2} x^{2} - 7 x + 7

(2 x - 5)^{2}

y = + x^{2} + 6 x + 3

4 (x + 2)^{2} + 5