What is the foci+(x+2)^2-4 ?

The foci+(x+2)^2-4 is (-2,-15/4)

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foci+(x+2)^2-4

foci

+ (x + 2)^{2} - 4

(- 2, - \frac{15}{4})

Solution steps

Rewrite

y = (x + 2)^{2} - 4

in the standard form:

4 \cdot \frac{1}{4} (y - (- 4)) = (x - (- 2))^{2}

(h, k) = (- 2, - 4), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, - 4)

along the y-axis

(- 2, - 4 + p)

= (- 2, - 4 + \frac{1}{4})

Refine

(- 2, - \frac{15}{4})