What is the foci y^2+2y+12x+25=0 ?

The foci y^2+2y+12x+25=0 is (-5,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2+2y+12x+25=0

foci

y^{2} + 2 y + 12 x + 25 = 0

(- 5, - 1)

Solution steps

Rewrite

y^{2} + 2 y + 12 x + 25 = 0

in the standard form

4 (- 3) (x - (- 2)) = (y - (- 1))^{2}

(h, k) = (- 2, - 1), p = - 3

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 2, - 1)

along the x-axis

(- 2 + p, - 1)

= (- 2 + (- 3), - 1)

Refine

(- 5, - 1)

(x - 3)^{2} = y - 7

- 3 x^{2} + 5 x

(x - 1)^{2} = - 2 y - 11

(x + 3)^{2} = 12 (y - 5)

x^{2} - 6 x