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Popular >

foci z^2+10z+5

Solution

foci

z^{2} + 10 z + 5

Solution

(- 5, - \frac{79}{4})

Solution steps

Rewrite

y = z^{2} + 10 z + 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 20)) = (z - (- 5))^{2}

(h, k) = (- 5, - 20), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 5, - 20)

along the y-axis

(- 5, - 20 + p)

= (- 5, - 20 + \frac{1}{4})

Refine

(- 5, - \frac{79}{4})

Popular Examples

foci x^2=5y foci

x^{2} = 5 y

foci-3x^2+3 foci

- 3 x^{2} + 3

foci y^2+14y+4x+45=0 foci

y^{2} + 14 y + 4 x + 45 = 0

foci+(x+2)^2-4 foci

+ (x + 2)^{2} - 4

foci (x-4)^2=-8(y+2)foci

(x - 4)^{2} = - 8 (y + 2)

Frequently Asked Questions (FAQ)

What is the foci z^2+10z+5 ?
The foci z^2+10z+5 is (-5,-79/4)