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Popular Geometry >

foci z^2+10z+5

Solution

foci

Solution

(- 5, - \frac{79}{4})

Solution steps

Rewrite

y = z^{2} + 10 z + 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 20)) = (z - (- 5))^{2}

(h, k) = (- 5, - 20), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 5, - 20)

along the y-axis

(- 5, - 20 + p)

= (- 5, - 20 + \frac{1}{4})

Refine

(- 5, - \frac{79}{4})

Graph

Popular Examples

foci y^2+14y+4x+45=0

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foci y^2+2y-4x+9=0

Frequently Asked Questions (FAQ)

What is the foci z^2+10z+5 ?
The foci z^2+10z+5 is (-5,-79/4)