What is (x^2)/(64)+(y^2)/(16)=1 ?

The solution to (x^2)/(64)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=8,b=4

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(x^2)/(64)+(y^2)/(16)=1

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 8, b = 4

Solution steps

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 4

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

x^{2} + y^{2} - 25 = 0

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

x^{2} - y^{2} = 14

What is (x^2)/(64)+(y^2)/(16)=1 ?
The solution to (x^2)/(64)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=8,b=4