What is the foci x^2-y^2=14 ?

The foci x^2-y^2=14 is (2sqrt(7),0),(-2sqrt(7),0)

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foci x^2-y^2=14

foci

x^{2} - y^{2} = 14

(27, 0), (- 27, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 14 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 14, b = 14

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 14^{2} + 14^{2} : 27

(0 + 27, 0), (0 - 27, 0)

Refine

(27, 0), (- 27, 0)

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

x^{2} - y^{2} = 1

x^{2} + y^{2} - 32 x - 60 y + 1122 = 0