What is the foci (y-2)^2=8(x-1) ?

The foci (y-2)^2=8(x-1) is (3,2)

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foci (y-2)^2=8(x-1)

foci

(y - 2)^{2} = 8 (x - 1)

(3, 2)

Solution steps

Rewrite

(y - 2)^{2} = 8 (x - 1)

in the standard form:

4 \cdot 2 (x - 1) = (y - 2)^{2}

(h, k) = (1, 2), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(1, 2)

along the x-axis

(1 + p, 2)

= (1 + 2, 2)

Refine

(3, 2)

(y + 2)^{2} = - 16 (x + 5)

y^{2} + 4 x + 1 = 0

x = \frac{1}{12} y^{2}

x^{2} - 24 x - 12

s^{2} + 4 s + 20