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Popular >

foci y=x^2+5x+6

Solution

foci

y = x^{2} + 5 x + 6

Solution

(- \frac{5}{2}, 0)

Solution steps

Rewrite

y = x^{2} + 5 x + 6

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - (- \frac{5}{2}))^{2}

(h, k) = (- \frac{5}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{5}{2}, - \frac{1}{4})

along the y-axis

(- \frac{5}{2}, - \frac{1}{4} + p)

= (- \frac{5}{2}, - \frac{1}{4} + \frac{1}{4})

Refine

(- \frac{5}{2}, 0)

Popular Examples

foci x^2+3x-4 foci

x^{2} + 3 x - 4

foci (x-3)^2=8(y-2)foci

(x - 3)^{2} = 8 (y - 2)

foci (x+3)^2=24(y-1)foci

(x + 3)^{2} = 24 (y - 1)

foci 3-2x-x^2 foci

3 - 2 x - x^{2}

foci x^2+x-1 foci

x^{2} + x - 1

Frequently Asked Questions (FAQ)

What is the foci y=x^2+5x+6 ?
The foci y=x^2+5x+6 is (-5/2 ,0)