What is the vertices (y^2)/(36)-(x^2)/(64)=1 ?

The vertices (y^2)/(36)-(x^2)/(64)=1 is (0,6),(0,-6)

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vertices (y^2)/(36)-(x^2)/(64)=1

vertices

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 8

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

x^{2} + (y + 2)^{2} = 4

x = 4 y^{2} + 8 y - 3

\frac{x ^{2}}{16} + y^{2} = 1

y^{2} = - 20 x

x^{2} - 4 x - 8 y + 2 = 0

What is the vertices (y^2)/(36)-(x^2)/(64)=1 ?
The vertices (y^2)/(36)-(x^2)/(64)=1 is (0,6),(0,-6)