x=4y^2+8y-3

Lösung

x = 4 y^{2} + 8 y - 3

(h, k) = (- 7, - 1), p = \frac{1}{16}

Schritte zur Lösung

x = 4 y^{2} + 8 y - 3

Rewrite

x = 4 y^{2} + 8 y - 3

in the standard form

4 \cdot \frac{1}{16} (x - (- 7)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 7, - 1), p = \frac{1}{16}