What is the foci 3y^2-6y-x=0 ?

The foci 3y^2-6y-x=0 is (-35/12 ,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 3y^2-6y-x=0

foci

3 y^{2} - 6 y - x = 0

(- \frac{35}{12}, 1)

Solution steps

Rewrite

3 y^{2} - 6 y - x = 0

in the standard form

4 \cdot \frac{1}{12} (x - (- 3)) = (y - 1)^{2}

(h, k) = (- 3, 1), p = \frac{1}{12}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 3, 1)

along the x-axis

(- 3 + p, 1)

= (- 3 + \frac{1}{12}, 1)

Refine

(- \frac{35}{12}, 1)

- 2 x^{2} - 16 x - 25

- x^{2} + 3 x = 2 y + 3

- x^{2} + 10 x - 23

(y - 2)^{2} = 4 (x + 3)

x^{2} - 5 x + 6