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Popular >

foci-x^2+10x-23

Solution

foci

- x^{2} + 10 x - 23

Solution

(5, \frac{7}{4})

Solution steps

Rewrite

y = - x^{2} + 10 x - 23

in the standard form

4 (- \frac{1}{4}) (y - 2) = (x - 5)^{2}

(h, k) = (5, 2), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(5, 2)

along the y-axis

(5, 2 + p)

= (5, 2 + (- \frac{1}{4}))

Refine

(5, \frac{7}{4})

Popular Examples

foci (y-2)^2=4(x+3)foci

(y - 2)^{2} = 4 (x + 3)

foci x^2-5x+6 foci

x^{2} - 5 x + 6

foci (x+2)^2=-6(y-1)foci

(x + 2)^{2} = - 6 (y - 1)

foci y=+x^2+81 foci

y = + x^{2} + 81

foci+x^2-2x-1 foci

+ x^{2} - 2 x - 1

Frequently Asked Questions (FAQ)

What is the foci-x^2+10x-23 ?
The foci-x^2+10x-23 is (5, 7/4)