What is the foci y=x^2-64 ?

The foci y=x^2-64 is (0,-255/4)

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foci y=x^2-64

foci

y = x^{2} - 64

(0, - \frac{255}{4})

Solution steps

Rewrite

y = x^{2} - 64

in the standard form:

4 \cdot \frac{1}{4} (y - (- 64)) = (x - 0)^{2}

(h, k) = (0, - 64), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 64)

along the y-axis

(0, - 64 + p)

= (0, - 64 + \frac{1}{4})

Refine

(0, - \frac{255}{4})

y = 5 x^{2} + 6 x - 7

2 x^{2} - 12 x + 3

9 y^{2} - 6 y - 9 - x = 0

x - x^{2}

x^{2} + 5 x + 6