What is the foci 2x^2-12x+3 ?

The foci 2x^2-12x+3 is (3,-119/8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 2x^2-12x+3

foci

2 x^{2} - 12 x + 3

(3, - \frac{119}{8})

Solution steps

Rewrite

y = 2 x^{2} - 12 x + 3

in the standard form

4 \cdot \frac{1}{8} (y - (- 15)) = (x - 3)^{2}

(h, k) = (3, - 15), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, - 15)

along the y-axis

(3, - 15 + p)

= (3, - 15 + \frac{1}{8})

Refine

(3, - \frac{119}{8})

9 y^{2} - 6 y - 9 - x = 0

x - x^{2}

x^{2} + 5 x + 6

x^{2} + 6 x + 16 y + 121 = 0

y = \frac{1}{24} x^{2}