What is the foci (x-5)^2=4(y-3) ?

The foci (x-5)^2=4(y-3) is (5,4)

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foci (x-5)^2=4(y-3)

foci

(x - 5)^{2} = 4 (y - 3)

(5, 4)

Solution steps

Rewrite

(x - 5)^{2} = 4 (y - 3)

in the standard form:

4 \cdot 1 \cdot (y - 3) = (x - 5)^{2}

(h, k) = (5, 3), p = 1

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(5, 3)

along the y-axis

(5, 3 + p)

= (5, 3 + 1)

Refine

(5, 4)

y^{2} - 10 y + 4 x + 21 = 0

0.3 x^{2} - 66 x + 23114

\frac{x}{25} - y^{2} = 1

y = 2 x^{2} - 2

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)