What is the foci x/(25)-y^2=1 ?

The foci x/(25)-y^2=1 is (2501/100 ,0)

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foci x/(25)-y^2=1

foci

\frac{x}{25} - y^{2} = 1

(\frac{2501}{100}, 0)

Solution steps

Rewrite

\frac{x}{25} - y^{2} = 1

in the standard form:

4 \cdot \frac{1}{100} (x - 25) = (y - 0)^{2}

(h, k) = (25, 0), p = \frac{1}{100}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(25, 0)

along the x-axis

(25 + p, 0)

= (25 + \frac{1}{100}, 0)

Refine

(\frac{2501}{100}, 0)

y = 2 x^{2} - 2

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

- x^{2} + 8 x - 12

y = x^{2} + 5 x - 14

y^{2} - 10 y - 12 x + 13 = 0