Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

vertices y=x^2+3vertices foci ((x+2)^2)/9+((y-3)^2)/(16)=1foci (x^2)/(64)+(y^2)/(16)=1asymptotes of (x^2)/(36)-(y^2)/(64)=1asymptotes x^2+y^2-25=0

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2-14x+2y+41=0 ?

    The center x^2+y^2-14x+2y+41=0 is (7,-1)