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Popular >

foci x^2+7x+12

Solution

foci

x^{2} + 7 x + 12

Solution

(- \frac{7}{2}, 0)

Solution steps

Rewrite

y = x^{2} + 7 x + 12

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{1}{4})) = (x - (- \frac{7}{2}))^{2}

(h, k) = (- \frac{7}{2}, - \frac{1}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{7}{2}, - \frac{1}{4})

along the y-axis

(- \frac{7}{2}, - \frac{1}{4} + p)

= (- \frac{7}{2}, - \frac{1}{4} + \frac{1}{4})

Refine

(- \frac{7}{2}, 0)

Popular Examples

foci (3x-4)(4x-3)-2x foci

(3 x - 4) (4 x - 3) - 2 x

foci 0.5x^2-2x-2 foci

0.5 x^{2} - 2 x - 2

foci y=2x^2-39 foci

y = 2 x^{2} - 39

foci y^2+6y+8x+25=0 foci

y^{2} + 6 y + 8 x + 25 = 0

foci (x^5+x^4+x^3+x^2+x+1)/(x^3+1)foci

\frac{x ^{5} + x ^{4} + x ^{3} + x ^{2} + x + 1}{x ^{3} + 1}

Frequently Asked Questions (FAQ)

What is the foci x^2+7x+12 ?
The foci x^2+7x+12 is (-7/2 ,0)