What is the foci y^2+6y+8x+25=0 ?

The foci y^2+6y+8x+25=0 is (-4,-3)

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foci y^2+6y+8x+25=0

foci

y^{2} + 6 y + 8 x + 25 = 0

(- 4, - 3)

Solution steps

Rewrite

y^{2} + 6 y + 8 x + 25 = 0

in the standard form

4 (- 2) (x - (- 2)) = (y - (- 3))^{2}

(h, k) = (- 2, - 3), p = - 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 2, - 3)

along the x-axis

(- 2 + p, - 3)

= (- 2 + (- 2), - 3)

Refine

(- 4, - 3)

\frac{x ^{5} + x ^{4} + x ^{3} + x ^{2} + x + 1}{x ^{3} + 1}

y^{2} - 12 y + 4 x + 4 = 0

x^{2} = - 20 y

x^{2} = - 36 y

y = 64 - x^{2}