What is the foci 290(8x+0.5x^2-1.4) ?

The foci 290(8x+0.5x^2-1.4) is (-8,-5617879/580)

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foci 290(8x+0.5x^2-1.4)

foci

290 (8 x + 0.5 x^{2} - 1.4)

(- 8, - \frac{5617879}{580})

Solution steps

Rewrite

y = 290 (8 x + 0.5 x^{2} - 1.4)

in the standard form

4 \cdot \frac{1}{580} (y - (- 9686)) = (x - (- 8))^{2}

(h, k) = (- 8, - 9686), p = \frac{1}{580}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 8, - 9686)

along the y-axis

(- 8, - 9686 + p)

= (- 8, - 9686 + \frac{1}{580})

Refine

(- 8, - \frac{5617879}{580})

y = - 3 x^{2} - 12 x - 9

2 - 3 x^{2}

x^{2} + 5 x - 14

x^{2} + 8 x - 12 y + 88 = 0

- x^{2}

What is the foci 290(8x+0.5x^2-1.4) ?
The foci 290(8x+0.5x^2-1.4) is (-8,-5617879/580)