What is the foci x^2+8x-12y+88=0 ?

The foci x^2+8x-12y+88=0 is (-4,9)

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foci x^2+8x-12y+88=0

foci

x^{2} + 8 x - 12 y + 88 = 0

(- 4, 9)

Solution steps

Rewrite

x^{2} + 8 x - 12 y + 88 = 0

in the standard form

4 \cdot 3 (y - 6) = (x - (- 4))^{2}

(h, k) = (- 4, 6), p = 3

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 4, 6)

along the y-axis

(- 4, 6 + p)

= (- 4, 6 + 3)

Refine

(- 4, 9)

- x^{2}

y = x^{2} - 15 x

6 x^{2} + 12 y - 18 = 0

y = x^{2} - 3 x^{2}

y = x^{2} - 3 x^{1}