What is the foci y=(x^2x^1)/x ?

The foci y=(x^2x^1)/x is (0, 1/4)

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foci y=(x^2x^1)/x

foci

y = \frac{x ^{2} x ^{1}}{x}

(0, \frac{1}{4})

Solution steps

Rewrite

y = \frac{x ^{2} x ^{1}}{x}

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{4})

Refine

(0, \frac{1}{4})

(x - 3)^{2} = 8 (y - 5)

y^{2} = - 24 x

- x^{2} + 5 x - 7

y = \frac{6 x}{7} \frac{4 x}{3}

y = 4 x^{2}